For the reaction, PCl _ 5 ( ~g ) PCl _ 3 ( ~g )+ Cl _ 2 ( ~g )
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
For the reaction,
\(\mathrm{PCl}_{5}(\mathrm{~g}) \longrightarrow \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\)
\(\mathrm{PCl}_{5}(\mathrm{~g}) \longrightarrow \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\)
- ∆H = ∆U
- ∆H > ∆U
- ∆H < ∆U
- None of these
Answer
(B) ∆ H > ∆ U
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