The enthalpy of neutralization of the given reaction H _ 2 SO _ 4 +2 NaOH Na _ 2 SO _ 4…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
The enthalpy of neutralization of the given reaction \(\mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{y}\) kcal is:
- y kcal
- - y kcal
- + y/2 kcal
- - y/2 kcal
Answer
(D) - y/2 kcal
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