Four charges +q, +q, –q and –q are placed respectively at the corners A, B, C & D of a…
Physics · JEE Main · NTA Exams — Electrostatics
Four charges +q, +q, –q and –q are placed respectively at the corners A, B, C & D of a square of side a. The potential and field at the centre O of the square are respectively \(\frac{1}{4 \pi \epsilon_{0}}\) times
- zero, 4q/a2
- zero , \(\frac{4 \sqrt{2} q}{a^{2}}\)
- \(4 \sqrt{2 q / a} ; 4 q / a^{2}\)
- \(4 \sqrt{2 q} ; 4 \sqrt{2 q / a^{2}}\)
Answer
(B) zero , 4 2 q a^ 2
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