The radius of a spherical Gaussian surface is R and a charge of 10 μC lies at its center…
Physics · JEE Main · NTA Exams — Electrostatics
The radius of a spherical Gaussian surface is R and a charge of 10 μC lies at its center. Another equal and opposite charge lies at a distance 2R from the center of the spherical surface. The total flux passing through the surface will be
- zero
- 1.13 x 106 V-m
- 2.26 x 106 V-m
- 3.39 x 106 V-m
Answer
(A) zero
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In finding the electric field using Gauss Law the formula | E |= q_ k n k _ n |A| is applicable. In the…
- An alpha nucleus of energy 1 2 mv ^ 2 bombards a heavy nuclear target of charge Ze. Then the distance of…
- A dielectric slab is placed between the plates of a parallel plate capacitor. The capacitor is connected to a…
- A conducting sphere of radius R and carrying charge Q is joined to an uncharged conducting sphere of radius…
- In the given circuit if point C is connected to the earth and a potential of +2000 V is given to point A, the…
- An infinite number of identical capacitors each of capacitance 1mF are connected as in adjoining figure. Then…
- Two identical conducting balls A and B have positive charges q 1 and q 2 respectively but q 1 ≠ q 2 . The…
- There are four capacitors which have same plate area, dielectric medium but different distances between the…
More Electrostatics questions · Browse all practice questions