A parallel plate air capacitor has capacity 'C' distance of separation between plates is…

Physics · JEE Main · NTA ExamsElectrostatics

A parallel plate air capacitor has capacity 'C' distance of separation between plates is 'd' and potential difference 'V' is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is:
  1. \(\frac{C^{2} V^{2}}{2 d^{2}}\)
  2. \(\frac{C^{2} V^{2}}{2 d}\)
  3. \(\frac{C V^{2}}{Z d}\)
  4. \(\frac{C V^{2}}{d}\)

Answer

(A) C^ 2 V^ 2 2 d^ 2

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Electrostatics questions · Browse all practice questions