Two concentric, thin metallic spheres of radii R 1 and R 2 (R 1 > R 2 ) bear charges Q 1…
Physics · JEE Main · NTA Exams — Electrostatics
Two concentric, thin metallic spheres of radii R1 and R2 (R1 > R2) bear charges Q1 and Q2 respectively. Then the potential at radius r between R1 and R2 will be \(\left(K=\frac{1}{4 \pi \epsilon_{0}}\right)\)
- K (Q1 + Q2) / r
- K (Q1/r + Q2/R2)
- K (Q2/r + Q1/R1)
- K (Q1/R1 + Q2/R2)
Answer
(C) K (Q 2 /r + Q 1 /R 1 )
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