A charged oil drop is suspended in uniform field of 3×10 4 V/m, so that it neither falls…
Physics · JEE Main · NTA Exams — Electrostatics
A charged oil drop is suspended in uniform field of 3×104 V/m, so that it neither falls nor rises. The charge on the drop will be
(take the mass of the drop = 9.9 × 10–15 kg and g = 10 m/s2)
(take the mass of the drop = 9.9 × 10–15 kg and g = 10 m/s2)
- 3.3 × 10–18 C
- 3.2 × 10–18 C
- 1.6× 10–18 C
- 4.8 × 10–18 C
Answer
(A) 3.3 × 10 –18 C
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