Two capacitors C 1 and C 2 are charged to 120 V and 200 V respectively. It is found that…
Physics · JEE Main · NTA Exams — Electrostatics
Two capacitors C1 and C2 are charged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be made zero. Then
- 5C1 = 3C2
- 3C1 = 5C2
- 3C1 + 5C2 = 0
- 9C1 = 4C2
Answer
(B) 3C 1 = 5C 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Which of the following may be discontinuous across a charged conducting surface ?
- Given below are two statements. STATEMENT - 1: A capacitor exists with potential difference V. A proton is…
- Two positive charges of magnitude q are placed at the ends of a side 1 of a square of side 2a. Two negative…
- A charge 3 C experiences a force of 3000 N when placed in a uniform electric field. The potential difference…
- A capacitor made of two circular plates each of radius 12 cm and separated by 5.0 mm. The capacitor is being…
- A 5 µF capacitor is fully charged across a 12 V battery. It is then disconnected from the battery and…
- The distance between H + and Cl – ions in HCl molecule is 1.28Å. What will be the potential due to this…
- The field at a distance r from a long string of charge per unit length λ is
More Electrostatics questions · Browse all practice questions