Two positive charges of magnitude q are placed at the ends of a side 1 of a square of…
Physics · JEE Main · NTA Exams — Electrostatics
Two positive charges of magnitude q are placed at the ends of a side 1 of a square of side 2a. Two negative charges of the same magnitude are kept at the other corners. Starting from rest, if a charge Q moves from the middle of side 1 to the centre of square, its kinetic energy at the centre of square is
- \(\frac{1}{4 \pi \varepsilon_{0}} \frac{2 \mathrm{qQ}}{\mathrm{a}}\left(1-\frac{1}{\sqrt{5}}\right)\)
- zero
- \(\frac{1}{4 \pi \varepsilon_{0}} \frac{2 \mathrm{qQ}}{\mathrm{a}}\left(1+\frac{1}{\sqrt{5}}\right)\)
- \(\frac{1}{4 \pi \varepsilon_{0}} \frac{2 \mathrm{qQ}}{\mathrm{a}}\left(1-\frac{2}{\sqrt{5}}\right)\)
Answer
(A) 1 4 _ 0 2 qQ a (1- 1 5 )
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