Two charges of 4 µC each are placed at the corners A and B of an equilateral triangle of…
Physics · JEE Main · NTA Exams — Electrostatics
Two charges of 4 µC each are placed at the corners A and B of an equilateral triangle of side length 0.2 m in air. The electric potential at C is \(\left(\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} \frac{\mathrm{~N}-\mathrm{m}^{2}}{\mathrm{C}^{2}}\right)\)
- 9 × 104 V
- 18 × 104 V
- 36 × 104 V
- 72 × 104 V
Answer
(C) 36 × 10 4 V
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