If the electric flux entering and leaving an enclosed surface respectively is φ 1 and φ 2…
Physics · JEE Main · NTA Exams — Electrostatics
If the electric flux entering and leaving an enclosed surface respectively is φ1 and φ2, the electric charge inside the surface will be
- (φ2 – φ1) ε0
- \(\frac{\left(\phi_{1}+\phi_{2}\right)}{\varepsilon_{0}}\)
- \(\frac{\left(\phi_{2}-\phi_{1}\right)}{\varepsilon_{0}}\)
- (φ1 + φ2) ε0
Answer
(A) ( φ 2 – φ 1 ) ε 0
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