Two seconds after projection, a projectile is traveling in a direction inclined at 30^ to…
Physics · NEET · NTA Exams — Kinematics
Two seconds after projection, a projectile is traveling in a direction inclined at \(30^{\circ}\) to the horizontal. After one more second of flight in air it is traveling horizontally. Then the velocity of projection is \(\text { [take } g=10 \mathrm{~m} / \mathrm{s}^{2} \text { ] }\)
- \(20 \mathrm{~m} / \mathrm{s} \text { and } \angle 60^{\circ}\)
- \(20 \sqrt{3} \mathrm{~m} / \mathrm{s} \text { and } \angle 60^{\circ}\)
- \(10 \mathrm{~m} / \mathrm{s} \text { and } \angle 30^{\circ}\)
- None of these
Answer
(B) 20 3 ~m / s and 60^
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A small block slides down an inclined plane starting from the rest. Friction is absent. If 5_ n is the…
- Two ends of a train moving with a constant acceleration, pass a certain point with velocity u and v. The…
- A certain vector in the xy plane has an x -component of 12 m and a y -component of 8 m . It is then rotated…
- A body is moving in a circular path of diameter 0.2 m at the speed which increases uniformly. If the speed of…
- The position vector of a particle is determined by the expression The distance traversed in first 10 sec is…
- The co-ordinates of a moving particle at any time 't' are given by x= t^ 3 and y= t^ 3 . The speed of the…
- The relation between time t and distance x is t=a x^ 2 +b x where a and b are constants. The acceleration is
- The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half…