The relation between time t and distance x is t=a x^ 2 +b x where a and b are constants…
Physics · NEET · NTA Exams — Kinematics
The relation between time t and distance x is \(t=a x^{2}+b x\) where a and b are constants. The acceleration is
- \(-2 \mathrm{av}^{3}\)
- \(2 \mathrm{av}{ }^{2}\)
- \(-2 a b v^{2}\)
- \(2 b v^{3}\)
Answer
(A) -2 av ^ 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t 1 if the…
- A police car is traveling in a straight line with constant speed v. A truck traveling in the same direction…
- Two balls A and B are thrown simultaneously. A is thrown vertically upwards with a speed of 20 m/s from the…
- The X and Y components of a force F acting at 30º to x -axis are respectively [KCET 2012]
- The displacement of a particle is represented by the following equation 5=4 t^ 3 +6 t^ 2 +5 t+9 , where S is…
- An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by: d v d t =-2.5 v where v is the…
- A soldier jumps out from an aeroplane with a parachute. After dropping through a distance of 19.6 m, he opens…
- A ball is dropped from a bridge 122.5 m above a river. After the ball has been falling for two seconds, a…