The position vector of a particle is determined by the expression The distance traversed…
Physics · NEET · NTA Exams — Kinematics
The position vector of a particle is determined by the expression
The distance traversed in first 10 sec is [DPMT 2002]
- 500 m
- 300 m
- 150 m
- 100 m
Answer
(A) 500 m
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A boy sitting on the topmost berth in the compartment of a train, which is just going to stop on a railway…
- A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t 1 if the…
- A river is flowing at the rate of 6 km/hr. A swimmer across with a velocity of 9 km/hr. What will be the…
- Figure below shows the distance-time graph of the motion of a car. It follows from the graph that the car is 5
- The relation between time t and distance x is t=a x^ 2 +b x where a and b are constants. The acceleration is
- Ship A is sailing towards north-east with velocity v =30 i +50 j km/hr where points east and , north. Ship B…
- A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the n ^…
- A particle moves along a straight line such that its displacement at any time t is given by 5= [t^ 3 -6 t^ 2…