A body starts from rest and moves with a uniform acceleration. The ratio of the distance…
Physics · NEET · NTA Exams — Kinematics
A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the \(\mathrm{n}^{\mathrm{th}}\) sec to the distance covered in n sec is
- \(\frac{2}{n}-\frac{1}{n^{2}}\)
- \(\frac{2}{n}+\frac{1}{n^{2}}\)
- \(\frac{2}{n^{2}}-\frac{1}{n}\)
- \(\frac{1}{n}-\frac{1}{n^{2}}\)
Answer
(D) 1 n - 1 n^ 2
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