The maximum height attained by a projectile when thrown at an angle θ with the horizontal…
Physics · NEET · NTA Exams — Kinematics
The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then, θ is equal to
- \(\tan ^{-1}(2)\)
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{4}\)
- \(\tan ^{-1}\left(\frac{1}{2}\right)\)
Answer
(A) ^ -1 (2)
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