A particle is moving with velocity v = k ( y i + x j ) , where k is a constant. The…
Physics · NEET · NTA Exams — Kinematics
A particle is moving with velocity \(\overrightarrow{\mathrm{v}}=\mathrm{k}(\hat{\mathrm{y}} \hat{\mathrm{i}}+\mathrm{x} \hat{\mathrm{j}})\), where k is a constant. The general equation for its path is
- \(x^{2}+y^{2}=\text { constant }\)
- \(y=x^{2}+\text { constant }\)
- \(y^{2}=x+\text { constant }\)
- \(x y=\operatorname{con} 5 \tan t\)
Answer
(A) x^ 2 +y^ 2 = constant
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A person completes a round on a circular path of 360 m in 6 minutes. The average speed of the person in m/s is
- If a=A ^ 2 s i n t when A and are constants. Find velocity of the particle. ( 'a' is the acceleration of the…
- A car is moving uniformly at a constant velocity of 40 km/h, then its acceleration is
- A plane is revolving around the earth with a speed of 100 km/hr at a constant height from the surface of…
- A body, thrown upwards with some velocity reaches the maximum height of 50 m. Another body with double the…
- A car is traveling at 72 km/h and is 20 m from a barrier when the driver puts on the brakes. The car hits the…
- A certain vector in the xy plane has an x -component of 12 m and a y -component of 8 m . It is then rotated…
- An elevator in which a man is standing is moving upward with a speed of 10 m/s uniformly. If the man drops a…