The curve x y=c(c>0) and the circle x^ 2 +y^ 2 =1 touch at two points, then distance…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The curve \(x y=c(c>0)\) and the circle \(x^{2}+y^{2}=1\) touch at two points, then distance between the points of contact is
- 1
- 2
- \(2 \sqrt{2}\)
- none of these
Answer
(B) 2
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