If u= ( x^ 2 +y^ 2 x+y ) , then the value of x L x +y L y is:
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If \(u=\log \left(\frac{x^{2}+y^{2}}{x+y}\right)\), then the value of \(x \frac{\partial L}{\partial x}+y \frac{\partial L}{\partial y}\) is:
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Answer
(B) 0
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