_ x 1 2 x^ 3 -1 ^ 6 2 x is equal to
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{x \rightarrow 1} \frac{\cos 2 x^{3}-1}{\sin ^{6} 2 x}\) is equal to
- \(\frac{1}{16}\)
- \(-\frac{1}{16}\)
- \(\frac{1}{32}\)
- \(-\frac{1}{32}\)
Answer
(D) - 1 32
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