In the above question calculate ∆S gas if process is carried out at constant volume :
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
In the above question calculate ∆Sgas if process is carried out at constant volume :
- \(5 \mathrm{R} \ell \mathrm{n} 2\)
- \(\frac{3}{2} \mathrm{R} \ell \mathrm{n} 2\)
- \(3 \mathrm{R} \ell \mathrm{n} 2\)
- \(-3 \mathrm{R} \ell \mathrm{n} 2\)
Answer
(C) 3 R n 2
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