For the reaction : C _ 2 H _ 4 ( ~g )+3 O _ 2 ( ~g ) 2 CO _ 2 ( ~g )+2 H _ 2 O ( ) at 298…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
For the reaction :
\(\mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{CO}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\ell)\)
at 298 K, ∆U = – 1415 kJ.
If R = 0.0084 kJ K–1, then ∆H is equal to
\(\mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{CO}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\ell)\)
at 298 K, ∆U = – 1415 kJ.
If R = 0.0084 kJ K–1, then ∆H is equal to
- –1400 kJ
- –1410 kJ
- –1420 kJ
- –1430 kJ
Answer
(C) –1420 kJ
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