Water is boiled under a pressure of 1.0 atm. When an electric current of 0.50 A from a…

Chemistry · JEE Main · NTA ExamsChemical Thermodynamics

Water is boiled under a pressure of 1.0 atm. When an electric current of 0.50 A from a 12V supply is passed for 300 s through a resistance in thermal contact with it, it is found that 0.789 g of water is vaporised. Calculate the molar internal energy and enthalpy changes at boiling point (373.15 K).
  1. \(40.6 \mathrm{~kJ} \mathrm{~mol}^{-1}, 37.5 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  2. \(41.06 \mathrm{~kJ} / \mathrm{mol}^{-1}, 37.96 \mathrm{~kJ} / \mathrm{mol}^{-1}\)
  3. \(42.5 \mathrm{~kJ} \mathrm{~mol}^{-1}, 45.5 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  4. \(40.92 \mathrm{~kJ} / \mathrm{mol}^{-1}, 38.4 \mathrm{~kJ} / \mathrm{mol}^{-1}\)

Answer

(B) 41.06 ~kJ / mol ^ -1 , 37.96 ~kJ / mol ^ -1

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