The range of the function f( x )= x ^ 2 + 1 x ^ 2 +1
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The range of the function \(f(\mathrm{x})=\mathrm{x}^{2}+\frac{1}{\mathrm{x}^{2}+1}\)
- [1, ∞)
- [2, ∞)
- \(\left[\frac{3}{2}, \infty\right)\)
- None of these
Answer
(A) [1, ∞ )
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