The value of _ r=0 ^ ^ -1 ( 1 1+r+r^ 2 ) is equal to :
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The value of \(\sum_{r=0}^{\infty} \tan ^{-1}\left(\frac{1}{1+r+r^{2}}\right)\) is equal to :
- \(\frac{\pi}{2}\)
- \(\frac{3 \pi}{4}\)
- \(\frac{\pi}{4}\)
- None of these
Answer
(A) 2
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