If f(x+y)=f(x)+f(y)-x y-1 for all x, y E and f(1)=1 , then the number of solutions of…
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
If \(f(x+y)=f(x)+f(y)-x y-1\) for all \(x, y E\) and \(f(1)=1\), then the number of solutions of \(f(n)=n_{1} n \in \mathbb{N}\) is
- One
- Two
- Four
- None of these
Answer
(A) One
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