If the inverse trigonometric functions take principal values, then ^ -1 ( 3 10 ( ^ -1 ( 4…
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
If the inverse trigonometric functions take principal values, then
\(\cos ^{-1}\left(\frac{3}{10} \cos \left(\tan ^{-1}\left(\frac{4}{3}\right)\right)+\frac{2}{5} \sin \left(\tan ^{-1}\left(\frac{4}{3}\right)\right)\right)\) is equal to
\(\cos ^{-1}\left(\frac{3}{10} \cos \left(\tan ^{-1}\left(\frac{4}{3}\right)\right)+\frac{2}{5} \sin \left(\tan ^{-1}\left(\frac{4}{3}\right)\right)\right)\) is equal to
- 0
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{3}\)
- \(\frac{\pi}{6}\)
Answer
(D) 6
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