Number of solutions of the equation ^ -1 ( 1 2 x +1 )+ ^ -1 ( 1 4 x +1 )= ^ -1 ( 2 x ^ 2…
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
Number of solutions of the equation
\(\tan ^{-1}\left(\frac{1}{2 \mathbf{x}+1}\right)+\tan ^{-1}\left(\frac{1}{4 \mathbf{x}+1}\right)=\tan ^{-1}\left(\frac{2}{\mathbf{x}^{2}}\right)\) is
- 1
- 2
- 3
- 4
Answer
(A) 1
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