Let f(x)=2^ -(x) and g(x)= array c -1 if x>0 0 if x=0 1 if x where (x) is fractional part…
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
Let \(f(x)=2^{-(x)}\) and \(g(x)=\) \[\left\{\begin{array}{c} -1 \text { if } x>0 \\ 0 \text { if } x=0 \\ 1 \text { if } x<0 \end{array}\right.\]
where \(\text { (x) }\) is fractional part of \(\mathbf{x}\). Then for all \(\mathbf{x}\), \(g[f(x)]\) is equal to
- 1
- \(f(x)\)
- \(g(x)\)
- -1
Answer
(D) -1
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The number of values of x , where the function f(x)= x+ ( 2 x) attains its maximum, is
- f (x) = x + x ^ 2 is a function from R → R. Then f (x) is
- The largest interval lying in (- 2 , 2 ) for which the function f(x)=4^ -x^ 2 + ^ -1 ( x 2 -1 ) + log (cos x)…
- The set of values of x satisfying the inequalities (x – 1) (x – 2) 0 is
- Find the domain of f(x)= cosec x +( x)^ 1 / 3 .
- A function f from the set of natural numbers to integers defined by f(n)= array ll n-1 2 , & when n is odd …
- The value of x for which x-3 4 -x 2 – x > 2x – 8
- The domain of the function f(x)= ^ -1 (3-x) (|x|-2)
More Sets, Relations and Functions questions · Browse all practice questions