f (x) = x + x ^ 2 is a function from R → R. Then f (x) is
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
f (x) = x + \(\sqrt{\mathrm{x}^{2}}\)is a function from R → R. Then f (x) is
- injective
- surjective
- bijective
- none of these
Answer
(D) none of these
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