If a f (x + 1) + b f ( 1 x+1 )=x, x ≠ −1, a ≠ –b, then f (1) is equal to
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
If a f (x + 1) + bf \(\left(\frac{1}{x+1}\right)=x,\) x ≠ −1, a ≠ –b, then f (1) is equal to
- a + b
- a2 – b2
- \(\frac{1}{a+b}\)
- f(1) = 0
Answer
(D) f(1) = 0
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