If y=1+ x 1! + x ^ 2 2! + x ^ 3 3! + , then the value of d y d x is
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
If \(y=1+\frac{\mathbf{x}}{1!}+\frac{\mathbf{x}^{2}}{2!}+\frac{\mathbf{x}^{3}}{3!}+\ldots\), then the value of \(\frac{d y}{d x} \text { is }\)
- 0
- 1
- \(\mathbf{x}\)
- \(\mathbf{Y}\)
Answer
(D) Y
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