The set of values of x which satisfy the inequations 5x + 2 < 3x + 8 and x+2 x-1 <4 is
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The set of values of x which satisfy the inequations
5x + 2 < 3x + 8 and \(\frac{x+2}{x-1}<4\) is
5x + 2 < 3x + 8 and \(\frac{x+2}{x-1}<4\) is
- \((-\infty, 1)\)
- (2, 3)
- \((-\infty, 3)\)
- \((-\infty, 1) \cup(2,3)\)
Answer
(D) (- , 1) (2,3)
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