Range of f(x) = sin –1 x + tan –1 x + sec –1 x is

Mathematics · JEE Main · NTA ExamsSets, Relations and Functions

Range of f(x) = sin–1 x + tan–1 x + sec–1 x is
  1. \(\left(\frac{\pi}{4}, \frac{3 \pi}{4}\right)\)
  2. \(\left[\frac{\pi}{4}, \frac{3 \pi}{4}\right]\)
  3. \(\left\{\frac{\pi}{4}, \frac{3 \pi}{4}\right\}\)
  4. None of these

Answer

(C) 4 , 3 4

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