Range of f(x) = sin –1 x + tan –1 x + sec –1 x is
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
Range of f(x) = sin–1 x + tan–1 x + sec–1 x is
- \(\left(\frac{\pi}{4}, \frac{3 \pi}{4}\right)\)
- \(\left[\frac{\pi}{4}, \frac{3 \pi}{4}\right]\)
- \(\left\{\frac{\pi}{4}, \frac{3 \pi}{4}\right\}\)
- None of these
Answer
(C) 4 , 3 4
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