If f : R → S, define by f (x) = sin x – cos x + 1, is onto, then the interval of S is

Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions

1. [0, 1]
2. [–1, 1]
3. [0, 3]
4. [–1, 3]

Answer

(D) [–1, 3]

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• The function f : R → R defined by f (x) = (x – 1) (x – 2) (x – 3) is
• If f(x) is a polynomial function satisfying f(x) f ( 1 x )=f(x)+f ( 1 x ) and f(3)=28 . Find f(4)
• The value of ^ -1 3 4 + ^ -1 5 13 is :
• Let A = R - 3 , B = R - 1 , Let f : A → B be defined by f(x) = x-2 x-3 , then
• Solve for x : 3^ ( x ^ 2 -2 ) < ( 1 3 )^ (1- 3 2 | x | )
• Considering the principal values of the inverse trigonometric functions, the sum of all the solutions of the…
• If ^ -1 ( x 5 )+ cosec ^ -1 ( 5 4 )= 2 , then the value of x is
• The set of values of x satisfying the inequalities (x – 1) (x – 2) 0 is

More Sets, Relations and Functions questions · Browse all practice questions