The value of [ 2 - ^ -1 (- 3 2 ) ] is :
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The value of \(\sin \left[\frac{\pi}{2}-\sin ^{-1}\left(-\frac{\sqrt{3}}{2}\right)\right]\) is :
- \(\frac{\sqrt{3}}{2}\)
- \(-\frac{\sqrt{3}}{2}\)
- \(\frac{1}{2}\)
- \(-\frac{1}{2}\)
Answer
(C) 1 2
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