Let _ k=1 ^ 10 f(a+k)=16 (z^ 1 a -1 ) , where the function f satisfies f(x+y)=f(x) f(y)…
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
Let \(\sum_{k=1}^{10} f(a+k)=16\left(z^{1 a}-1\right)\), where the function f satisfies \(f(x+y)=f(x) f(y)\) for all natural numbers x, y and f(1) = 2. Then the natural number 'a' is:
- 2
- 3
- 16
- 4
Answer
(D) 4
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