If f(x)= array c 1- 4 x x^ 2 , x 0 array . then at x = 0
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If \[f(x)=\left\{\begin{array}{c}
\frac{1-\cos 4 x}{x^{2}}, x<0 \\
\frac{\sqrt{x}}{\sqrt{16+\sqrt{x}}-4}, x>0
\end{array}\right.\]
then at x = 0
- f (x) is continuous, when \(a=0\)
- f (x) is continuous, when \(\square=8\)
- f (x) is discontinuous for every value of a
- None of these
Answer
(B) f (x) is continuous, when =8
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