If y= _ u(x) ^ v(x) f(t) d t let us define d y d x in a different manner as d y d x =v^…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If \[y=\int_{u(x)}^{v(x)} f(t) d t\] let us define \(\frac{d y}{d x}\)in a different manner
as \(\frac{d y}{d x}=v^{\prime}(x) f^{2}(v(x))-u^{\prime}(x) f^{2}(u(x))\)and the equation of the tangent at
as \(y-b=\left(\frac{d y}{d x}\right)_{(a, b)}(x-a)\)
If \(y=\int_{x}^{x^{2}} t^{2}\) dt, then equation of tangent at x = 1 is
- y = x + 1
- x + y = 1
- y = x – 1
- y = x
Answer
(C) y = x – 1
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