The abscissa of a point on the curve xy = (a + x) 2 , the tangent at which cuts off equal…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The abscissa of a point on the curve xy = (a + x)2,
the tangent at which cuts off equal intercepts on the coordinate axes is
the tangent at which cuts off equal intercepts on the coordinate axes is
- \(-\mathrm{a} / \sqrt{2}\)
- \(\sqrt{2} \mathrm{a}\)
- \(\sqrt{2} \mathrm{a} / 2\)
- \(-\sqrt{2} \mathrm{a}\)
Answer
(A) - a / 2, (C) 2 a / 2
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