For a transistor, in a common emitter arrangement, the alternating current gain β is…
Physics · JEE Advanced · NTA Exams — Electronic Devices
For a transistor, in a common emitter arrangement, the alternating current gain β is given by
- \(\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{V}_{\mathrm{C}}}\)
- \(\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{C}}}\right)_{\mathrm{V}_{\mathrm{C}}}\)
- \(\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{E}}}\right)_{\mathrm{V}_{\mathrm{C}}}\)
- \(\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{E}}}{\Delta \mathrm{I}_{\mathrm{C}}}\right)_{\mathrm{V}_{\mathrm{C}}}\)
Answer
(A) = ( I _ C I _ B )_ V _ C
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