The curve for which the sum of the lengths of the tangent and subtangent at any of its…

Mathematics · JEE Advanced · NTA Exams — Differential Equations

1. y = ln | c (k²x²–1)|
2. \(\mathrm{y}=\frac{1}{\mathrm{k}} \ln \left|\mathrm{c}\left(\mathrm{k}^{2} \mathrm{x}^{2}-1\right)\right|\)
3. y = ln |k (c²x² +1)|
4. y = ln |k (c² x² –1)|

Answer

(B) y = 1 k | c ( k ^ 2 x ^ 2 -1 ) |

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