Explanation:tion of differential equation dy dx = y + _ 0 ^ 1 ydx , y (0) = 1 is :
Mathematics · JEE Advanced · NTA Exams — Differential Equations
Explanation:tion of differential equation
\(\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{y}+\int_{0}^{1} \mathrm{ydx},\)y (0) = 1 is :
\(\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{y}+\int_{0}^{1} \mathrm{ydx},\)y (0) = 1 is :
- \(y=\frac{1}{3-e}\left(2 e^{x}+e+1\right)\)
- \(y=\frac{1}{3+e}\left(2 e^{x}-e+1\right)\)
- \(y=\frac{1}{3-e}\left(2 e^{x}-e+1\right)\)
- none
Answer
(C) y= 1 3-e (2 e^ x -e+1 )
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