A curve passes through the point (1, 6 ) . Let the slope of the curve at each point ( x …
Mathematics · JEE Advanced · NTA Exams — Differential Equations
A curve passes through the point \(\left(1, \frac{\pi}{6}\right)\). Let the slope
of the curve at each point (x, y) be \(\frac{y}{x}+\sec \left(\frac{y}{x}\right),\)x > 0 . Then the equation of the curve is
of the curve at each point (x, y) be \(\frac{y}{x}+\sec \left(\frac{y}{x}\right),\)x > 0 . Then the equation of the curve is
Answer
(A)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let f : (0, ∞) → R be a differentiable function such that f^ (x)=2- f(x) x for all x ∈ (0, ∞) and f (1) ≠ 1…
- Let f : [0, ∞) → be a continuous function such that f(x)=1-2 x+ _ 0 ^ x e^ x-t f(t) d t for all x ∈[0, ∞)…
- The Explanation:tion of the differential equation dy dx = y x + ( y / x ) ^ ( y / x ) is
- Let y ( x ) be a solution of the differential equation (1 + e x ) y ′ + ye x = 1 . If y (0) = 2, then which…
- If y ( x ) satisfies the differential equation y ′ – y tan x = 2 x sec x and y (0) = 0, then
- The differential equation of all the ellipses centred at the origin and having their axes as co-ordinate axes…
- Explanation:tion of differential equation x^ 3 d y d x =y^ 3 +y^ 2 y^ 2 -x^ 2 is
- The differential equation d y d x = 1-y^ 2 y determines a family of circles with
More Differential Equations questions · Browse all practice questions



