Explanation:tion of the differential equation : (3 tan x + 4 cot y – 7) sin 2 y dx –…

Mathematics · JEE Advanced · NTA Exams — Differential Equations

1. \(\frac{3}{2} \cot ^{2} x-7 \cot x+\frac{7}{2} \tan ^{2} y-5 \tan y+4 \cot x \tan y=c\)
2. \(\frac{3}{2} \tan ^{2} x-7 \tan x+\frac{7}{2} \cot ^{2} y-5 \cot y+4 \tan x \cot y=c\)
3. 3 tan²y – 14 cot x.tan²y + 7 cot²x –10 tan y cot²x
   + 8 cot x. tan y + 2c cot²x tan²y = 0
4. 3 cot²y – 14cot x. cot²y + 7 cot²x + 10 cot y tan²x
   + 8 tan x . cot y = 0

Answer

(B) 3 2 ^ 2 x-7 x+ 7 2 ^ 2 y-5 y+4 x y=c, (C) 3 tan 2 y – 14 cot x.tan 2 y + 7 cot 2 x –10 tan y cot 2 x + 8 cot x. tan y + 2c cot 2 x tan 2 y = 0

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