The x-intercept of the tangent to a curve is equal to the ordinate of the point of…
Mathematics · JEE Advanced · NTA Exams — Differential Equations
The x-intercept of the tangent to a curve is equal to the ordinate of the point of contact. The equation of the curve through the point (1, 1) is
- \(\mathrm{ye}^{\frac{\mathrm{x}}{\mathrm{y}}}=\mathrm{e}\)
- \(x e^{\frac{x}{y}}=e\)
- \(x e^{\frac{y}{x}}=e\)
- \(\mathrm{ye}^{\frac{\mathrm{y}}{\mathrm{x}}}=\mathrm{e}\)
Answer
(A) ye ^ x y = e
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