A solution curve of the differential equation (x^ 2 +x y+4 x+2 y+4 ) d y d x -y^ 2 =0…
Mathematics · JEE Advanced · NTA Exams — Differential Equations
A solution curve of the differential equation \(\left(x^{2}+x y+4 x+2 y+4\right) \frac{d y}{d x}-y^{2}=0, x>0\) passes
through the point (1, 3). Then the solution curve
through the point (1, 3). Then the solution curve
- intersects y = x + 2 exactly at one point
- intersects y = x + 2 exactly at two points
- intersects y = (x + 2)2
- does not intersect y = (x + 3)2
Answer
(D) does not intersect y = ( x + 3) 2
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