If f (x) = x 3 – x 2 + 100x + 1001, then

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

If f (x) = x3 – x2 + 100x + 1001, then
  1. f (2000) > f (2001)
  2. \(f\left(\frac{1}{1999}\right)>f\left(\frac{1}{2000}\right)\)
  3. f (x + 1) > f (x – 1)
  4. f (3x – 5) > f (3x)

Answer

(B) f ( 1 1999 )>f ( 1 2000 ), (C) f (x + 1) > f (x – 1)

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Limit, Continuity and Differentiability questions · Browse all practice questions