If f (x) = x 3 – x 2 + 100x + 1001, then
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
If f (x) = x3 – x2 + 100x + 1001, then
- f (2000) > f (2001)
- \(f\left(\frac{1}{1999}\right)>f\left(\frac{1}{2000}\right)\)
- f (x + 1) > f (x – 1)
- f (3x – 5) > f (3x)
Answer
(B) f ( 1 1999 )>f ( 1 2000 ), (C) f (x + 1) > f (x – 1)
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