A charge +is fixed at each of the points x = x 0 , x = 3x 0 , x = 5x 0 , ..... ad inf. on…
Physics · JEE Advanced · NTA Exams — Electrostatics
A charge +is fixed at each of the points x = x0, x = 3x0, x = 5x0, ..... ad inf. on the x axis, and a charge –is fixed at each of the points x = 2x0, x = 4x0, x = 6x0, ...... ad inf. Here x0 is a positive constant. Take the electric potential at a point due to a charge at a distance r from it to be Q/(4πε0r). Then, the potential at the origin due to the above system of charges is
- 0
- \(\frac{\mathrm{q}}{8 \pi \varepsilon_{0} \mathrm{x}_{0} \mathrm{In} 2}\)
- ∞
- \(\frac{\mathrm{q} \operatorname{In} 2}{4 \pi \varepsilon_{0} \mathrm{x}_{0}}\)
Answer
(D) q In 2 4 _ 0 x _ 0
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