Two equal charges are separated by a distance d. A third charge placed on a perpendicular…
Physics · JEE Advanced · NTA Exams — Electrostatics
Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when
- \(x=\frac{d}{\sqrt{2}}\)
- \(x=\frac{d}{2}\)
- \(x=\frac{d}{2 \sqrt{2}}\)
- \(x=\frac{d}{2 \sqrt{3}}\)
Answer
(C) x= d 2 2
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